Check whether 6” can end with the digit 0 for any natural number n.
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Step-by-step explanation:
If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5
Prime factorisation of 6n = (2 ×3)n
It can be observed that 5 is not in the prime factorisation of 6n.
Hence, for any value of n, 6n will not be divisible by 5.
Therefore, 6n cannot end with the digit 0 for any natural number n.
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If any digit has the last digit 10 that means it divisible by 10.
The factor of 10=2×5,
So value of 6^n should be divisible by 2 and 5.
Both 6^n is divisible by 2 but not divisible by 5.
So, it can not end with 0.
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