Math, asked by deepalamba41, 2 months ago


Check whether 6" can end with the digit 0 for any natural number n.

Answers

Answered by minny68
2

6^n = (2 x 3)^n

= 2^n x 3^n

since, 2x5 are not exist

therefore, 6^n does not end with digit zero

hope it helps :)

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