check whether 6^n ends with digit zero for any natural number n
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If the number 6n ends with the digit zero (0), then it should be divisible by 5. We know any number with the unit place as 0 or 5 is divisible by 5. Therefore, the prime factorization of 6n doesn't contain prime number 5. Thus it proves that 6n cannot end with the digit 0 for any natural number n.
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Answer:
no
Step-by-step explanation:
6^1 = 6
6^2 = 36
6^3 = 216
and so on...
If the number 6^n ends with the digit zero (0), then it should be divisible by 5. The prime factorization of 6^n doesn't contain prime number 5. Thus it proves that 6^n cannot end with the digit 0 for any natural number n.
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