Check whether 6n
can and with the digit ofar
any natural number n?
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Let us suppose 6n end with the digit zero for any natural number belonging to n.
6n is divisible by 5
It is clear that the factors of 6 are 2×3
By prime factorisation factors of 6 are (2×3)n
Hence it is clear from the above factor that there is no 5 in its factors....
So The fundamental theorem of arithmetic states that every composite number can be factorised as in the product of primes, and this factorisation is unique, apart from which prime factors occur....
Hence our supposition is wrong...
6n can't end with the digit zero for any natural number belonging to n...
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