check whether check whether 4 n can end with the digit 0 for any natural number N
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4^n can never end with 0
because according to the fundamental theorem of arithmetic no. with factors =(2×5)^n only end with 0
whereas 4^n=(2×2)^n
since 4^n does not have 5^n as its factor
hence it can't end with 0
H. P.
because according to the fundamental theorem of arithmetic no. with factors =(2×5)^n only end with 0
whereas 4^n=(2×2)^n
since 4^n does not have 5^n as its factor
hence it can't end with 0
H. P.
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