Question

check whether equation F.S=1/2mv^2 -1/2mu^2 is dimensionally correct, where m is mass of the body, v its final velocity,u its initial velocity,F is force
applied and s is the distance moved
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Answer 1

Answer:

Explanation:

F=MLT^-2

S=L

M=M

V=LT^-1

FS=1/2mv^2-1/2mu^2

MLT^-2( L)=M(LT^-1)^2-M(LT^-1)^2

1/2 is dimensionless