check whether P(X)=4x^3-4x^2-x+1 is a multiple of (2x-1)
Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:
Answered by
4
hey
p(x) = 4x^3 - 4x^2 - x + 1
2x - 1 = 0
x = 1/2
P(1/2) = 4(1/2)^3 - 4(1/2)^2 - (1/2) + 1
= 4(1/8) - 4(1/4) - 1/2 + 1
= 1/2 - 1 - 1/2 + 1
= 0
Similar questions