Question

check whether p(x) is a multiple of g(x) or not where p(x)=x cube minus x plus 1 g(x) =2 minus 3x

Answer 1

I think this is the right answer.Hope it helps....

Answer 2

Answer:

No

Step-by-step explanation:

$p(x)=x^3-x+1$

$g(x)=2-3x$

So, Dividend = $p(x)=x^3-x+1$

Divisor = $g(x)=2-3x$

Substitute divisor = 0

So,  $2-3x=0$

$x=\frac{2}{3}$

Substitute the value of x in Dividend

$p(\frac{2}{3})=(\frac{2}{3})^3-\frac{2}{3}+1$

$p(\frac{2}{3})=\frac{17}{27}$

Since the remainder is not 0

So, p(x) is not a multiple of g(x)