check whether p(x) is multiple of g(x) or not. i)(x)=x^3+27x^2-8x+18,g(x)=x-1
aryawan123:
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Answered by
25
Hello ☺️
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g(x) = x - 1
⇒ x - 1 = 0
⇒ x = 1
Putting the value of x in p (x), we get ;
x³ - 27 x² - 8x + 18
⇒ 1³ - 27 × 1² - 8 × 1 + 18
⇒ 1 - 27 - 8 + 18
⇒ 19 - 35
⇒ 16
Hence, p ( x ) is not the multiple of g ( x ).
_______________________
Thanks !!
_______________________
g(x) = x - 1
⇒ x - 1 = 0
⇒ x = 1
Putting the value of x in p (x), we get ;
x³ - 27 x² - 8x + 18
⇒ 1³ - 27 × 1² - 8 × 1 + 18
⇒ 1 - 27 - 8 + 18
⇒ 19 - 35
⇒ 16
Hence, p ( x ) is not the multiple of g ( x ).
_______________________
Thanks !!
Answered by
13
Answer: p(x) is not multiple of g(x)
as r(x)is not equal to zero.
as r(x)is not equal to zero.
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