Question

Check whether the equations 2x-3y = 5 and 4x-6y = 15 are consistent. Also verify by graphical representation.

Answer 1

Answer:

plzzz give me brainliest ans and plzzzz follow me

Answer 2

Answer:

In line 2x - 3y = 5 , value of x = 0 then y = $\frac{-5}{3}$  and  y = 0 then  x =  $\frac{5}{2}$.

In line 4x - 6y = 15, value of x = 0 then  y = $\frac{5}{-2}$  and y = 0 then  x =  $\frac{15}{4}$

Step-by-step explanation:

In this question

We have given that

2x - 3y = 5

4x - 6y = 15

So, 2x - 3y - 5 = 0

4x - 6y - 15 = 0

Then, a_1 = 2, b_1 = -3, c_1 = -5

b_1 = 4, b_2 = -6, c_2 = -15

$\frac{a_1}{a_2}$ =  $\frac{2}{4}$

$\frac{a_1}{a_2}$ =  $\frac{1}{2}$

$\frac{b_1}{b_2}$ =  $\frac{-3}{-6}$

$\frac{b_1}{b_2}$ =  $\frac{1}{2}$

$\frac{c_1}{c_2}$ =  $\frac{-5}{-15}$

$\frac{c_1}{c_2}$ =  $\frac{1}{3}$  

Therefore, $\frac{a_1}{a_2}$ ≠ $\frac{b_1}{b_2}$ ≠ $\frac{c_1}{c_2}$

So, equation are inconsistent

Then, 2x + 3y -5 = 0

Putting x = 0,                               Putting y = o,

0 - 3y - 5 = 0                                2x  - 5 = 0

y = $\frac{-5}{3}$                                                x =  $\frac{5}{2}$

Similarly, 4x - 6y - 15 = 0

Putting x = 0,                               Putting y = o,

0 - 6y - 15 = 0                                  4x - 15 = 0

y = $\frac{15}{-6}$                                            x =  $\frac{15}{4}$

y = $\frac{5}{-2}$

Therefore , In line 2x - 3y = 5 , value of x = 0 then y = $\frac{-5}{3}$  and  y = 0 then  x =  $\frac{5}{2}$.

In line 4x - 6y = 15, value of x = 0 then  y = $\frac{5}{-2}$  and y = 0 then  x =  $\frac{15}{4}$