Math, asked by prahasanreddy, 4 days ago

Check whether the following are factors of x3 - 5x² – 2x+24 or not. (ii) (x + 3) (iii) (x + 2) (iv) (X + 8 X () (x + 4) 15.​

Answers

Answered by singhkalikotayaditi
0

Step-by-step explanation:

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Class 9

>>Maths

>>Polynomials

>>Remainder Theorem

>>Determine which of the foll...

Question

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Determine which of the following polynomials has (x+1) a factor:

(i) x

3

+x

2

+x+1

(ii) x

4

+x

3

+x

2

+x+1

(iii) x

4

+3x

3

+3x

2

+x+1

(iv) x

3

−x

2

−(2+

2

)x+

2

Medium

Solution

verified

Verified by Toppr

Apply remainder theorem

x+1=0

x=−1

Put the value of x=−1 in all equations.

(i) x

3

+x

2

+x+1=(−1)

3

+(−1)

2

+(−1)+1=−1+1−1+1=0

Then x+1 is the factor of equation

(ii) x

4

+x

3

+x

2

+x+1=(−1)

4

+(−1)

3

+(−1)

2

+(−1)+1=1−1+1−1+1=1

This is not zero.Then x+1 is not the factor of equation

(iii) x

4

+3x

3

+3x

2

+x+1=(−1)

4

+3(−1)

3

+3(−1)

2

+(−1)+1=1

This is not zero.Then x+1 is not the factor of equation

(iv)x

3

−x

2

−(2+

2

)x+

2

=(−1)

3

−(−1)

2

−(2+

2

)(−1)+

2

=−1−1+2−

2

+

2

=0

This is zero. Then x+1 is the factor of equation

Answered by preeti353615
0

Answer:

(x + 2) is a factor of x^3 -5x^2 -2x + 24 .

Step-by-step explanation:

Take x + 3

x = -3

x^3 -5x^2 -2x + 24

= (-3)^3 - 5(-3)^2  – 2(-3) + 24

=- 27 -5(9)+6 + 24

= -27 -45 + 30

= -42

So (x + 3) is not factor

Take x + 2

x = -2

x^3 -5x^2 -2x + 24

= (-2)^3 - 5(-2)^2  – 2(-2) + 24

=- 8 -5(4)+4 + 24

= -8 -20 + 28

= 0

So (x + 2) is a factor

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