Question

Check whether the following are quadratic equation x²-3x+1=(x-2)²

Answer 1

Answer:

Step-by-step explanation:

x*2-3x+1=(x-2)*2

Quadratic equation is in the form of

px*2+qx+r=0

So,x*2-3x+1= x*2+4x-4

So x*2 + 4x -4 -x*2 +3x -1 =0

7x -5=0

Hence it is not in form of

Px*2+qx+r=0

So it is not quadratic .

Answer 2

Answer:

It's not a quadratic equation.

Step-by-step explanation:

For a polynomial to be a quadratic equation, it must have a highest degree '2' contained upon its variable.

So, Let's check whether the given equation has a highest degree '2' or not!

x^2 - 3x + 1 = (x - 2)^2

x^2 - 3x + 1 = x^2 -4x + 4

x^2 - x^2 -3x + 4x + 1 - 4 = 0

x - 3 = 0

After simplifying the given equation, we get (x-3) = 0 and it can be clearly observed that the highest degree of this equation is '1' and not '2'.

Thus, from the above fact it can be concluded that given equation is not a quadratic equation!