Math, asked by rupaa1212, 9 months ago

Check whether the following are quadratic equations or not.
1
x -  \frac{3}{x}  =  {x}^{2}
2
 {x}^{2}  - 3x = 0
3
 {x}^{2}  + 6x - 4 = 0
4
 \sqrt{3}  {x}^{2}  - 2x  +  \frac{1}{2}  = 0
5
(2 x + 1 )(3 x + 2 )=6 (x -1)( x - 2 )
6
 {x}^{2}  +   \frac{1}{x {}^{2} }  = 5
7
(x +  \frac{1}{x} )  {}^{2}  = 3(x +  \frac{1}{x} ) + 4

Answers

Answered by jadoo0
0

Answer:

1234567..... I don't understand.....

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