Question

check whether the following are quadratic equations x³-4x²-x+1=(x-2)³​

Answer 1

Step-by-step explanation:

For LHS,,

${x }^{3} - {4x}^{2} - x + 1......(1)$

For RHS,,

$(x - 2) {}^{3} = x^{3}-6x^{2}+12x-8....(2)$

From eq (1) and (2)

${x}^{3} - {4x}^{2} - x + 1 =x^{3}-6x^{2}+12x-8\\ =>- {4x}^{2} - x + 1+6x^{2}-12x+8=0\\=>2x^{2}-13x+9$

Hence,, the given equation is a quadratic equation as it is in the form of ax²+bx+c=0..

Hope it helps ❣️❣️

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

${\bf{\green{x^3-4x^2-x+1=(x-2)^3}}}$

${\bf{\green{x^3-4x^2-x+1=x^3-8-3(2x)(x-2))}}}$

${\bf{\green{-4x^2-x+1=-8-6x^2+12x}}}$

${\bf{\green{-4x^2+6x^2-x-12x+1+8=0}}}$

${\bf{\green{2x^2-13x+9=0}}}$

${\bf{\green{it is in the form }}}$

${\bf{\green{=>ax^2+bx-c=0}}}$

${\bf{\blue{so,it is a}}}$

${\bf{\red{QUADRATIC EQUATION }}}$