Question

check whether v=u-2as² is dimensionally correct or not​

Answer 1

Answer:

Dimension of v=LT^-1

Dimension of u=LT^-1

Dimension of 2aS^2=L^3T^-2

Therefore equation is not dimensionally correct

Explanation:

According to principle of homogenety of dimension

Answer 2

Dimension of v = LT^-1

Dimension of u = LT^-1

Dimension of 2as² = L^3T^-2

To check the correctness of physical equation, v = u-2as² , Where 'u' is the initial velocity, 'v' is the final velocity, 'a' is the acceleration and s is the displacement, we have [L.H.S.] = [R.H.S.] for correct this equatuion but we can see that L.H.S is not equal to R.H.S. Hence  v = u-2as² is dimensionally not​ correct.