Check whether ( x- 1 ) is a factor of 4x³+5x² -3x + 6.
Answers
Answered by
7
It is not a factor because remainder is not 0 it is 12..
x-1=0
x=1
4+5-3+6=4+5+3=4+8=12
sanayaa:
please check answer
i think it is wrong
no the answer is not wrong..
Answered by
11
Heyya !!
Given:-
( x- 1 ) is a factor of 4x³+5x² -3x + 6.
x - 1 = 0
x = 1
p[x] = 4x³+5x² -3x + 6.
p [ 1 ] = 4 × 1³ + 5 ×1² - 3×1 + 6
4 + 5 -3 + 6 = 0
9 - 3 + 6 = 0
6+ 6 = 0
12 = 0
Here , LHS is not equal to RHS.
Hence ,
( x- 1 ) is not a factor of 4x³+5x² -3x + 6.
Given:-
( x- 1 ) is a factor of 4x³+5x² -3x + 6.
x - 1 = 0
x = 1
p[x] = 4x³+5x² -3x + 6.
p [ 1 ] = 4 × 1³ + 5 ×1² - 3×1 + 6
4 + 5 -3 + 6 = 0
9 - 3 + 6 = 0
6+ 6 = 0
12 = 0
Here , LHS is not equal to RHS.
Hence ,
( x- 1 ) is not a factor of 4x³+5x² -3x + 6.
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