check whether x=√2, -2√2 are the solutions of x^2+√2x-4=0 or not
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p(x) = x^2+√2x-4
p ( √2) = (√2)^2+√2(√2)-4
=2+2-4
=0
p(-2√2) = (-2√2)^2+√2(-2√2)-4
= 8 -4-4
= 0
hence , x=√2 , -2√2 are solutions of
x^2+√2x-4
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