Math, asked by kjosem4, 5 months ago

check whether x-2 is a factor of p(X)=2x²-3x²+3x-10​

Answers

Answered by chaturbisht45
0

Answer:

p(x) = 2x²-3x²+3x-10

x-2

x=2

p(2) = 2(2)²-3(2)²+3(2)-10

= 8-12+6-10

= -22+14

= -8

Since

The value is not equal to zero.

hence,

x-2 is not a factor of 2x²-3x²+3x-10

HOPE IT WILL HELP

Attachments:
Answered by LilBabe
77

Question

check whether x-2 is a factor of p(X)=2x²-3x²+3x-10

Answer

Given:- p(X)=2x²-3x²+3x-10

p(X) = -x²+3x-10

To check:x-2 is a zero of p(X) = x²-3x+10

Solution

Taking x-2=0 ; x = 2

Now

p(X) = -x²+3x-10

p(2) = (-2²)+3(2)-10

p(2) = 4 + 6 - 10

→p(2) = 10 - 10

→p(2) = 0

Since, the polynomial p(2) is equal to zero, [x-2] is a zero of the given polynomial p(X)=2x²-3x²+3x-10.

Let's sum up by substituting the value of x

2x²-3x²+3x-10.

2(2²)-3(2²)+3×2-10

(8-12)+(6-10)

4-4

0

Hence verified

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