Solve for x : x-1/x+2+x-3/x-4
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Answers
Correct Question :-
- Solve for x: (x-1/x-2) + (x-3/x-4) = 10/3 ..
Solution :-
→ (x-1/x-2) + (x-3/x-4) = 10/3
Taking LCM ,
→ [(x-1)(x-4) + (x-2)(x-3)] / (x-2)(x-4)= 10/3
→ [ (x² - 5x+ 4)+ (x² - 5x +6) ] / (x^2 -6x +8) = 10/3
Cross - Multiply,
→ 3(2x² -10 x +10) = 10(x² - 6x +8)
→ 6x² -30x + 30 = 10x² - 60x + 80
→ 10x² - 6x² - 60x + 30x + 80 - 30 = 0
→ 4x² - 30x + 50 = 0
→ 2(2x² - 15x + 25) = 0
→ 2x² - 15x + 25 = 0
Splitting The Middle Term Now,
→ 2x² - 10x - 5x + 25 = 0
→ 2x(x - 5) - 5(x - 5) = 0
→ (x - 5)(2x - 5) = 0
Putting Both Equal to Zero Now,
→ x - 5 = 0
→ x = 5 (Ans).
Or,
→ 2x - 5 = 0
→ 2x = 5
→ x = (5/2) (Ans.)
Hence, Value of x is 5 or (5/2).
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Question-
Solve for x : x-1/x+2+x-3/x-4
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Solution-
➠x-1/x+2+x-3/x-4 = 10/3
➠[(x-1)(x-4) + (x-2)(x-3)] ÷ (x-2)(x-4) = 10/3
➠[(x² - 5x + 4) + (x² - 5x + 6)] ÷ (x² - 6x + 8) = 10/3
➠3(2x²-10x+10) = 10(x² - 6x + 8)
➠6x² - 30x + 30 = 10x² - 60x + 80
➠10x² - 6x² - 60x + 30x + 80 - 30 = 0
➠4x² - 30x + 50 = 0
➠2(2x²-15x + 25) = 0
➠2x² -15x + 25 = 0
➠2x² - 10x - 5x + 25 = 0
➠2x(x -5 ) - 5(x-5) = 0
➠(x -5)(2x - 5) = 0
➠x - 5 = 0
➠x = 5