Question

check whether (x+5) and (x+6) are the factor of x^2+11x+30 (by factor theorem)

Answer 1

Answer:

1) (x+5) 2) (x+6)

if f(x)=x^2+11x+30 if f(x)=x^2+11x+30

divisor is (x+5) divisor is (x+6)

reminder is f(‐5) reminder is f(‐6)

f(‐5)= (‐5)^2+11(-5)+30 f(‐6)=(‐6)^2+11(‐6)+30

=(25)+(‐55)+30 =36+(‐66)+30

=25‐55+30 =36‐66+30

=55‐55 =66‐66

=0 =0

yes , these two factors (x+5) , (x+6) of x^2+11x+30

Answer 2

Answer:

Yes, (x+5) & (x+6) are the factors of x^2 + 11x + 30.

Step-by-step explanation:

We have to find:-

(x+5) is a factor of x^2 + 11x + 30.

(x+5) = (x+ 5) = 0

=> x = -5

=Let p(x) = x^2 + 11x + 30.

= (-5)^2 + 11(-5) + 30

= 25 -55 + 30

= -30 + 30

= 0

Therefore, (x+5) is a factor of x^2 + 11x + 30.

We have to find:-

(x+6) is a factor of x^2 + 11x + 30.

(x+6) = 0

=> x = -6

= (-6)^2 + 11(-6) + 30

= 36 - 66 + 30

= -30 + 30

= 0

Therefore, (x+6) is a factor of x^2 + 11x + 30.

Please Mark As Brainlist.