check whether x+5 is a factor of x³ -125
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let x+5 = 0
x = -5
now,
p (x) = x³ -125
{putting x = -5}
p(-5) = -5³-125
p( -5)= -125 -125
p(-5) = 0
hence ..if value become 0 so,
x+5 is factor of x³-125
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