Check which of the following is a solution of 2x-Sy-10 A(0,2) (5,0) (8,5)
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Given equation is 2x−5y=10
In RHS we have 2x−5y
Put the given (5,0) we get
2x−5y=10
2×5−5×0
10−0=10
Hence RHS=10 and LHS=10
Both are equal
Then (5,0) is not the solution of equation 2x−5y=10
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