Question

check ( x+1 ) is a factor of x cube+ x square + x + 1

Answer 1

$x + 1 = 0 \\ x = - 1 \\ \\ x {}^{3} + x {}^{2} + 1 = 0 \\ ( - 1) {}^{3} + ( - 1) {}^{2} + 1 = 0 \\ - 1 + 1 + 1 = 0 \\ 1 = 0$
x+1 is not factor of x^3 + x^2+1

Answer 2

Let x-1=0..X=-1
By remainder theorem
if , X+1 is a factor of x³+x²+x+1
them by putting X=-1
The remainder must be zero..
putting X=-1
(-1)³+(-1)²+(-1)+1
-1+1-1+1
0
..Hence x+1 is a factor of x³+x²+X+1

Hope it would help you.
mark as brainliest