Question

Check (x-2) is a factor of x2+4x2-x+1=0

Answer 1

Answer:

Assume that x-2 is a factor of x²+4x²-x+1

x-2=0

x=2

substituting x=2 in the expression we get,

(2)²+4(2)²-2+1=  4+16-1=19

there fore x-2 is not a factor of the expression x²+4x²-x+1 (since the substitution process donot give 0)

Answer 2

(x-2) is not the factor of the given equation:

Step-by-step explanation:

$\ Given \ value:\\\\x^2+4x^2 -x+1=0\\\\\ check (x-2) \ is \ the \ factor \ of \ the \ given \equation\\\\\ Solution:\\\\ \ let \ p(x) = x^2+4x^2 -x+1\\\\\ p(x) = 5x^2 -x+1\\\\\ and \ x-2 =0\ is \ the \factor \ of \ equation \ so, x= 2 \ put \ the \ value \ in \ p(x)\\\\p(x) = 5(2)^2-(2)+1\\\\p(x) = 5(4)-(2)+1\\\\p(x) = 20-2+1\\\\p(x) = 18+1\\\\p(x)=19$

Learn more:

• Factor: https://brainly.in/question/11795891