Question

cheetah is the fastest land animal and can achieve peak velocity of 100 km/h up to a distance less than 500 m. if a cheetah spots it's prey at a distance of 100 M. what is the minimum time it will take to get its Prey .if the average velocity at end by it is 90 km/h

Answer 1

minimum distance = 100m
average velocity = 90 km/h = 90× 5/18 = 25 m/s

minimum time = 100/25 = 4s

It will take minimum 4 second to get to its prey

Answer 2

Heya.....!!!!

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It seems to be a long question but it's very easy if you read it carefully .

Given in the question :--

• Average Velocity - 90 km/h => 90 × 5/18 = 25 m

• Distance that cheetah has to cover - 100 m

We have to take out the minimum time that cheetah will take to get it's prey .

So ,, we know that Time = Distance/Speed .

Here ,
=> distance = 100
=> Speed = 25

Then Time = 100/25 = 4 sec

Time taken by cheetah to get catch it's prey is
→ 4 sec .


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