Question

cheetah starts from rest and accelerates at 2 metre per second square for 10 seconds calculate the final velocity and distance travelled

Answer 1

Initial speed = u= 0 m/s
Time = t =10 s
Acceleration = a= 2m/s2
Final velocity = V= ?
From FIRST equation of motion:
V= u+at
=0+2×10
=20m/s
From Second equation of motion:
S=ut+ 1/2at^2
=0xt+(1/2 )*2×10×10
=100m
Therefore, Final velocity=20m/s and DISTANCE travelled =100m

Answer 2

Given:intial velocity (u)= 0 ,
acceleration (a)= 2m/s²
time (t) =10s

From 1st eq of motion
v=u+at

v=0+2×10
v=20m/s

From 3rd eq of motion

v²=u²+2as

(20)² = 0 + 2× 2×s

400= 4s
s=400/4s= 100m
Final velocity= 20m/sec
Distance= 100m