Question

Cheetah starts from rest and accelerates at 2 metre per second for 10 sec. calculate the final velocity and the distance travelled

Answer 1

hey your ans is here

______

given

a=2

u=0(as he starts from rest)

t=10

v=?

we know
a=v-u/t
2=v-0/10
20m/sec=final velocity

now to take out distance

we know

v2=u2+2as
(20)2=(0)2+2×2×s
400=4s
s=100m=distance

______

Answer 2

HEYA!!
---------

Given that ,

Initial velocity u = 0 { he starts from rest }

Acceleration A= 2m /s2.

Time t = 10 seconds

Final velocity v = ?

Distance travelled s =?

Using the first equation of motion

V = U + AT

V =10× 2 = 20m/s .

Using second equation of motion,

$s = ut + \frac{1}{2} at {}^{2}$
S = 0 + 1/2 × 2 × 100

= 100m

+-----------------------------------------------------------------------------------------------------
----------------------------------------------------------------------------------------------------