Question

Cheetah starts from rest and accelerates at 2 metre per second for 10 sec. calculate the final velocity and the distance travelled

Answer 1

U=0m/s
A=2m/s²
T=10s
Since,
V=u+at
:. putting value
V=0+2×10
V=20m/s
Now,
V²=u²+2as
20²=2(2)s
400=4s
400/4=s
m=s
(ÆÑẞWĒR)

Answer 2

acceleration = 2m/s²

initial velocity, u = 0 (∵ it starts from rest)

time taken = 10 seconds

From laws of motion,

→ v = u + at

→ v = at

→ v = 2(10)

→ v = 20m/s

Again, s = ut + ¹/₂ at²

→ s = ¹/₂ at²

→ s = ¹/₂ (2)(10)²

→ s = 100 m

Thus, the cheetah travels a distance of 100 metres in 10 seconds and reaches a final velocity of 20 m/s

Hope it helps!!