Cheetah starts from rest and acceleration at 2 metre per second square for 10 seconds calculate the final velocity be the distance travelled
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Answered by
4
a= 2m/s²
u=0
time =10 sec
using the first equation of motion
v= u+at
v = 0+ (2×10)
v =20m/sec
u=0
time =10 sec
using the first equation of motion
v= u+at
v = 0+ (2×10)
v =20m/sec
Answered by
1
Answer:
D= 200 meters
V= 20 meter per second
Explanation:
We know that the formula for acceleration is,
A= Velocity/ Time
A= Acceleration
Here the given values are,
A=2 meter per second square
And,
Time= 10 seconds
Hence we can easily find out the distance, traveled and the required velocity
V=A x T
we need to make certain that all the units are of the same kind,
V= 2 x 10
V= 20 meter per second
Now, we know the velocity(speed), by applying the simple distance, speed time formula we can know the distance,
D= S x T
D= V x T
D= 20 x 10
D= 200 meters
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