Question

CHEMISTRY ASSIGNMENT

Sketch the phase diagram of the system NH3/N2H4 given that the two substances do not form a compound with each other, that NH3 freezes at -78.0°C, N2H4 freezes at +2.0°C, that a eutectic is formed when the mole fraction of N2H4 is 0.07, and that the eutectic melts at -80°C.

$\huge{\textbf{URGENT !!!!!!!!!!!!!!!!!!!!!!!!!!!!}}$

Answer 1

${\large{\bold{\bf{\underline{Chemistry \; question}}}}}$

${\sf{Question}}$

☑ Sketch the phase diagram of the system NH₃/N₂H₄ given that the two substances do not form a compound with each other, that NH₃ freezes at -78.0°C, N₂H₄ freezes at +2.0°C, that a eutectic is formed when the mole fraction of N₂H₄ is 0.07, and that the eutectic melts at -80°C.

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${\sf{Meaning}}$

☑ This question says that we have to draw a sketch of the system NH₃/N₂H₄ here given that the two substances do not form a compound with each other! and NH₃ freezes at -78.0°C, N₂H₄ freezes at +2.0°C, that a eutectic is formed when the mole fraction of N₂H₄ is 0.07, and that the eutectic melts at -80°C.

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${\sf{Diagram \: or \: sketch}}$

Kindly see from the attachment.

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${\sf{Knowledge}}$

Compound defination -

These are pure substance that are composed of two or more different elements in fixed proportion by mass. The property of a compound are entirely differ from those of elements from which these are made. Some chemical elements are Oxygen , Carbon, Silicon etc.

There are two types of Compound -

$\: \: \: \:{\bullet{\leadsto}}$ Organic compound.

$\: \: \: \:{\bullet{\leadsto}}$ Inorganic compounds

❶ Organic compound - The compounds obtained from living sources are called organic compound. The term organic is now applied to hydrocarbon and their derivatives. Examples - Protein, Fat, Oils etc.

❷ Inorganic compounds - The compounds obtained from non - living sources are called organic compound. For example - Common salt, Marble, Washing soda etc.

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Freezing point definition -

Freezing point state that the temperature at which the liquid becomes solid.

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Mole fraction -

${\sf{\longmapsto X_{solvent} = \dfrac{Mole \: of \: solute}{Total \: solution \: mole}}}$

${\sf{\longmapsto X_{solute} = \dfrac{Mole \: of \: solute}{Total \: solution \: mole}}}$

Where,

${\rightarrow}$ ${\sf{X_{solute} \: + X_{solvent} = 1}}$

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NH₃ -

NH₃ is the chemical formula of ammonia. It is composed of one nitrogen atom and 3 hydrogen atom. Ammonia is colourless. Ammonia is lighter than air. And it come in shape of triagonal pyrarmid. It's molar mass is 17.031 g/mol. It's melting point is -77.73 °C

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N₂H₄ -

Hydrazine is the chemical name of N₂H₄ . It is mainly used as a foaming agent in preparing polymer foams. It is an inorganic compound . It's odour is like ammonia. Hydrazine is highly toxic unless handled in solution as e.g., hydrazine hydrate.Its molar mass is 32.0452 g/mol. It's melting point is 2 °C

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Let's see how to calculate molecular mass of elements

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Question 1 Calculate the molecular mass of C₂H₆

Here C is carbon atom and H is hydrogen atom.

➝ Mass of C is 12

➝ Mass of C₂ is 12 × 2

➝ Mass of C₂ is 24

➝ Mass of H is 1

➝ Mass of H₆ is 6 × 1

➝ Mass of H₆ is 6

➝ Molecular mass of C₂H₆ is 24 + 6 = 30

➝ Molecular mass of C₂H₆ is 30

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Question 2 Calculate the molecular mass of C₂H₄

Here C is carbon atom and H is hydrogen atom.

➝ Mass of C is 12

➝ Mass of C₂ is 12 × 2

➝ Mass of C₂ is 24

➝ Mass of H is 1

➝ Mass of H₄ is 4 × 1

➝ Mass of H₄ is 4

➝ Molecular mass of C₂H₄ is 24 + 4 = 28

➝ Molecular mass of C₂H₄ is 28

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Question 3 Calculate the molecular mass of NH₃

Here N is nitrogen atom and H is hydrogen atom.

➝ Mass of N is 14

➝ Mass of N is 14

➝ Mass of H is 1

➝ Mass of H₃ is 3 × 1

➝ Mass of H₃ is 3

➝ Molecular mass of NH₃ is 14 + 3 = 17

➝ Molecular mass of NH₃ is 17

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Question 4 Calculate the molecular mass of CH₃OH

Here C is carbon atom , H is hydrogen atom , O is oxygen atom.

➝ Mass of C is 12

➝ Mass of H is 1

➝ Mass of H₃ is 3 × 1

➝ Mass of H₃ is 3

According to the question,

➝ Total mass of H atom in compound = 3 + 1 = 4

➝ Mass of O is 16

➝ Molecular mass of CH₃OH is 12 + 4 + 16 = 16 + 16 = 32

➝ Molecular mass of CH₃OH is 32

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Question 5 Calculate the molecular mass of O₂

➝ Mass of O is 16

➝ Mass of O₂ is 16 × 2

➝ Mass of O₂ is 32

➝ Molecular mass of O₂ is 32

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