Chemistry Numerical
b) 7.1 g of chlorine reacts completely with iron to form FeCl3
Calculate the i) weight of Fe required ii) weight of ferric chloride formed
(with working please :D)
Thank you so much in advance!
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Answer:
Fe + 3Cl --> FeCl3 Fe = 56
MM = 56 +35.5 x 3 MM = 56 +35.5 x 3 Cl = 35.5
= 56 + 106.5 = 56 + 106.5
=162.5 amu =162.5 amu
106.5g of Cl --> 162.5g of FeCl3
therefore 7.1g of Cl --> 162.5/106.5 x 7.1 (7.1 cancels 106.5 to get 15)
= 162.5/15 = 10.833g (33 is recurring)
therefore weight of Fe = Weight of Cl3 - Weight of Cl
= 10.833 - 7.1
=3.733 (33 is recurring again)
Explanation:
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