Question

CHemistry Question:-
At what temperature will a given mass of a gas occupy a volume of 200L .If it occupies a volume of 260L at a temperature of 30°C.Pressure remaining the constant?​

Answer 1

Answer:-

Initial condition:-

• V1=200L
• T1=?

Final conditions:-

• V2=260L
• T2=30°C

Convert it to kelvin:-

$\\ \sf\longmapsto 1C=273K$

$\\ \sf\longmapsto 30°C=273+30$

$\\ \sf\longmapsto 30°C=303K$

Now

According to Charles law.

$\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}$

$\\ \sf\longmapsto \dfrac{200}{T_1}=\dfrac{260}{363}$

$\\ \sf\longmapsto T_1=\dfrac{303\times 200}{260}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ T_1=233K}}}$