Question

Chetan opened a savings bank account on 5 April ,2009 with a deposit of ₹1,00,400 .He closed it after 2 years
.If the bank paid him 6% interest per annum ,what amount did he receive?

Answer 1

Answer:

Amount=P+SI, Then find SI=P*T*R%/100=100400*2*6/100=1004*12=12048

Then amount is, 12048+100400=112448

Answer 2

The amount he receives is ₹ 1,12,448.

Step-by-step explanation:

Given:

• Principal 'p' = ₹1,00,400
• Rate 'r' = 6%
• Time 't' = 2 years

The simple interest is given by

$= > si = \frac{p \times r \times t}{100}$

$= > si = \frac{100400 \times 6 \times 2}{100}$

$= > si = 1004 \times 12$

$= > si = \: 12048$

The amount is given by

$= > amount = p + si$

$= > amount = 100400 + 12048$

$= > amount = 112448$

The amount he receives is ₹ 1,12,448.