Question

Chiku, Tipu and Pinku have some candies with each. Five times the number of candies with Pinku equals seven times the number of candies with Chiku while five times the number of candies with Chiku equals seven times the number of candies with Tipu. What is the minimum number of candies that can be there with all three of them put together?

Answer 1

Answer:

109

Explanation:

---> Let the candies with Chiku, Pinku and Tipu be a,b and c respectively.

---> Given, 5b = 7a, and 5a = 7c

---> 25b = 35a & 35a = 49c

---> 25b = 35a = 49c => (b/49) = (a/35) = (c/25)

---> The least possible integral values for a,b & c will be a = 35 , b = 49 & c = 25

---> Total = 35+49+25 = 109