Question

Child drops a ball from height of 10 m assume that its velocity increases uniformly at the rate of 10 m per second square find the velocity with which the boys ball strikes the ground

Answer 1

the total hight = 10 m
uniform velocity = 10m/s^2

total velocity = total hight * velocity per unit time

= 10* 10 = 100m/s^2

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Answer 2

    ⒶⓃⓈⓌⒺⓇ    

Acceleration(a) = 10 m/s²

Initial Velocity(u) = 0 m/s

Final velocity be 'v' m/s

g = 10 m/s²

Now Using equation of motion:

v² + u² = 2gh

v = √2gh

  = √200

  =  10√2 m s⁻¹

Now, Let the time be 't' sec.

Equation of motion:

  h = ut + 1/2gt²

⇒h = 1/2gt²

⇒t = √(2h/g)

⇒t = √2 sec

∴ Velocity = 10√2 m s⁻¹

∴ Time = √2 second