Question

Child playing with toys

A child is playing with a solid toy which is in the form of a right circular cylinder with a hemispherical shape at one end and a cone at the other end. Their common diameter is 4.2 cm and the height of the cylindrical and the conical portions are 12 cm and 7 cm respectively .find the TSA of the toy​

Answer 1

Answer:

Diameter of base of conical part=4.2cm

Diameter of base of cylindrical part=4.2cm

Diameter of hemispherical part=4.2m

Therefore radius=2.1cm

Height of conical part, h

1

=7cm

Height of cylindrical part, h

2

=12cm

Volume of toy=volume of cone +volume of cylinder+volume of hemisphere

=

3

1

πr

2

h

1

+πr

2

h

1

+

3

2

πr

3

=πr

2

(

3

h

1

+h

2

+

3

2r

)

=

7

22

×2.1×2.1(

3

7

+12+

3

2×2.1

)

=

7

22

×2.1×2.1×15.73

=218.02cm

3

Answer 2

I don’t know the answer
LoL