Question

Children have difficulty in _numbers two until the age of three

or four.

(a) grasping, as many as (b)to grasp, as big as

(c) grasping, greater than (d) having grasped, fewer​

Answer 1

Answer:

c) grasping, greater than.

it's my guess only.

Answer 2

Step-by-step explanation:

a man borrowed a sum of rs 12000 from his friend at the rate of 8%per annum for 3 years amd invested this amount on same day for 3 years at 12% per annum find his profitiii) Who is being referred to as ‘that voice from the world of men’?Here the Concept of Properties of Parallelogram has been used. Here we see we are given the different points and their relation in the parallelogram. Using this we can firstly find a relation between the different sides and then prove the required things.

Let's do it !!

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★ Correct Question :-

In the given figure ABCD is a Parallelogram in which P is the mid point of DC and Q is a point on AC such that CQ = ¼ AC. If PQ produced meets BC at R. Then proof R is a mod point of BC.

Refer to the attachment

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★ Solution :-

Given,

» Mid - point of DC = P

» Mid - point of AC = Q

» There is a parallelogram ABCD whose diagonals are AC and BD

» CQ = ¼ × AC

✒ Property :: In a Parallelogram, the diagonals bisect each other.

According to this property ;

~ For Diagonal AC :

→ AO = OC

~ For Diagonal BD :

→ BO = OD

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~ For Diagonal AC ::

We already know that,

→ AO = OC

Then,

\begin{gathered}\\\;\bf{\rightarrow\;\;\green{OC\;\;=\;\;\dfrac{1}{2}\;AC}}\end{gathered}→OC=21AC

Let this be equation i)

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~ For relation between CQ and OC ::

Its given that,

\begin{gathered}\\\;\bf{\rightarrow\;\;\red{CQ\;\;=\;\;\dfrac{1}{4}\;AC}}\end{gathered}→CQ=41AC

Taking ½ in common, we get

\begin{gathered}\\\;\bf{\Longrightarrow\;\;CQ\;\;=\;\;\dfrac{1}{2}\:\bigg(\dfrac{1}{2}\;AC\bigg)}\end{gathered}⟹CQ=21(21AC)

Applying equation i) here, we get

\begin{gathered}\\\;\bf{\Longrightarrow\;\;CQ\;\;=\;\;\dfrac{1}{2}\:\bigg(OC\bigg)}\end{gathered}⟹CQ=21(OC)

\begin{gathered}\\\;\bf{\Longrightarrow\;\;\orange{CQ\;\;=\;\;\dfrac{1}{2}\:OC}}\end{gathered}⟹CQ=21OC