Question

chirds AB and CD of a circle intersect inside the circle at point E. If AE=5.6,EB=10,CE=8,find ED​

Answer 1

Answer:

Step-by-step explanation:

For a given circle

Chords AB and CD are touch each other internally at point E.

AE=5.6, EB=10

CE=8, ED=?

By internal division of chords

AE×EB=CE×ED

5.6×10=8×ED

56=8×ED

56/8=ED

7=ED

i.e ED =7