Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2 ) with aqueous hydrochloric acid according to the reaction 4 HCl (aq) + MnO2 (s) → 2H2O (l) + MnCl2 (aq) + Cl2 (g) How many grams of HCl react with 5.0 g of manganese dioxide?
NCERT Class XII
Chemistry - Main Course Book I
Chapter 1. Some Basic Conpepts of Chemistry
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HCl : molar mass = 36.4
Mn O2 : 54.9 + 32 = 86.9
4 moles of HCl = 145.6 grams reacts with 1 mole of Mn O2 ie., 86.9 grams..
So mass of HCl that reacts with 5.0 grams of Manganese dioxide :
5 * 145.6 / 86.9 = 8.377 grams of HCl.
Mn O2 : 54.9 + 32 = 86.9
4 moles of HCl = 145.6 grams reacts with 1 mole of Mn O2 ie., 86.9 grams..
So mass of HCl that reacts with 5.0 grams of Manganese dioxide :
5 * 145.6 / 86.9 = 8.377 grams of HCl.
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