Question

Chlorine is prepared in the laboratory by treating manganese dioxide (MnO,) with
aqueous hydrochloric acid according to the reaction
4 HCI (aq) + Mno,(s) → 2H,0 (1) + MnCl,(aq) + Cl, (g)
How many grams of HCl react with 5.0 g of manganese dioxide? ?​

Answer 1

Answer:

5.0g of MnO

2

contains=

87mol

−1

g

5.0g

=0.0574 moles

4HCl(aq)+MnO

2

(s)⟶2H

2

O+MnCl

2

+Cl

2

(g)

1 mole of MnO

2

reacts with 4 mole of HCl

Thus, 0.0574 mole of MnO

2

will react with 4×0.0574 moles of HCl

=0.23 mole of HCl will react with 5g of MnO

2

Amount of HCl in 0.23 mole= 0.23×36.5 = 8.4g of HCl

Thus, 8.4g of HCl will react with 5g of MnO

2

.

Answered By

prarthana U

Explanation:

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Answer 2

Answer:

Explanation:

5.0g of MnO  2

contains=   87mol  −1  g

5.0g =0.0574 moles

4HCl(aq)+MnO  2  (s)⟶2H 2  O+MnCl 2+Cl  2  (g)

1 mole of MnO 2  reacts with 4 mole of HCl

Thus, 0.0574 mole of MnO  2  will react with 4×0.0574 moles of

HCl  =0.23 mole of HCl will react with 5g of MnO2  

Amount of HCl in 0.23 mole= 0.23×36.5 = 8.4g of HCl

Thus, 8.4g of HCl will react with 5g of MnO  2

​