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1 A vertical narrow glass tube of uniform cross-section, closed at one end has air
filled in it upto 40 cm of height, with a column of mercury of height 10 cm above it.
if the tube is gradually inclined in the vertical plane and brought to a position
making an angle of 60° with the vertical, then new length of air column entrapped
within the tube is (atmospheric pressure = 76 cm of Hg)
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Answer:
A vertical narrow glass tube of uniform cross-section
The height
=
40
c
m
of height
Column of mercury of height
=
10
c
m
Angle
=
60
°
P
=
h
ρ
g
P
×
40
×
A
=
ρ
1
×
(
50
)
×
A
⇒
ρ
1
=
45
45
+
1
×
(
45
−
x
)
×
ρ
2
h
1
=
44.47
c
m
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