Question

choices 10), 10), !
1 A vertical narrow glass tube of uniform cross-section, closed at one end has air
filled in it upto 40 cm of height, with a column of mercury of height 10 cm above it.
if the tube is gradually inclined in the vertical plane and brought to a position
making an angle of 60° with the vertical, then new length of air column entrapped
within the tube is (atmospheric pressure = 76 cm of Hg)​

Answer 1

Answer:

A vertical narrow glass tube of uniform cross-section

The height

=

40

c

m

of height

Column of mercury of height

=

10

c

m

Angle

=

60

°

P

=

h

ρ

g

P

×

40

×

A

=

ρ

1

×

(

50

)

×

A

⇒

ρ

1

=

45

45

+

1

×

(

45

−

x

)

×

ρ

2

h

1

=

44.47

c

m