Question

Choose and write the correct option in the following questions 1. An isosceles right triangle has areas.com. The length of its hypotese is ​

Answer 1

Answer:

both. I think so.

Step-by-step explanation:

pls mark me brain list

Answer 2

ANSWER

The length of hypotenuse will be,

√32

Step by Step:

(a) Given, area of an isosceles right triangle = 8 cm2

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cm

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cmIn ΔABC, using Pythagoras theorem

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cmIn ΔABC, using Pythagoras theoremAC2 = AB2 + BC2 = 42 + 42 = 16 + 16

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cmIn ΔABC, using Pythagoras theoremAC2 = AB2 + BC2 = 42 + 42 = 16 + 16⇒ AC2 = 32 ⇒ AC = √32 cm

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cmIn ΔABC, using Pythagoras theoremAC2 = AB2 + BC2 = 42 + 42 = 16 + 16⇒ AC2 = 32 ⇒ AC = √32 cm[taking positive square root because length is always positive]

(a) Given, area of an isosceles right triangle = 8 cm2Area of an isosceles triangle = 1/2 (Base x Height)⇒ 8 = 1/2 (Base x Base)[∴ base = height, as triangle is an isosceles triangle]⇒ (Base)2 =16 ⇒ Base= 4 cmIn ΔABC, using Pythagoras theoremAC2 = AB2 + BC2 = 42 + 42 = 16 + 16⇒ AC2 = 32 ⇒ AC = √32 cm[taking positive square root because length is always positive]Hence, the length of its hypotenuse is √32 cm.