Question

choose the correct ground state term symbol of high spin octahedral ir*3
a)³F
b)⁵D
c)⁴F
d)⁶S​

Answer 1

Answer:

Explanation:

Ir^+3=[Xe] 4f^14 5d^6

We write the ground state term as n+1 L

5d^6 is filled in orbitals as 2,1,1,1,1

Total spin=+2(2)+1(1)+0+1(-1)+1(-2)

Total spin=2

Spin 2 corresponds to D

So L=D

Number of unpaired electrons=n=4

n+1=5

So correct spin=⁵D

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