Question

Choose the correct option and solve

A current of 96.5 A is passed for 18 min between Nickel electrodes in 500mL solution of 2M Ni(NO3)2. The molarity of solution after electrolysis would be :-
1. 0.46 M
2. 0.92 M
3. 0.625 M
4. 1.25 M

Answer 1

Equation :

Ni²⁺ + 2e —> Ni

1 mole is deposited by : 96500 × 2= 193000 C

Moles of nickel in 500ml

(500 / 1000) × 2 = 1mole

The charge passed through :

18 × 60 × 96.5 = 104220 C

How many moles will this deposit :

104220 / 193000 = 0.54 moles

Remaining moles in the Sol:

1 - 0.54 = 0.46 moles

Molarity :

(1000/ 500) × 0.46 = 0.92 M

Answer 2

Answer:

Explanation:

Equation :

Ni²⁺ + 2e —> Ni

1 mole is deposited by : 96500 × 2= 193000 C

Moles of nickel in 500ml

(500 / 1000) × 2 = 1mole

The charge passed through :

18 × 60 × 96.5 = 104220 C

How many moles will this deposit :

104220 / 193000 = 0.54 moles

Remaining moles in the Sol:

1 - 0.54 = 0.46 moles

Molarity :

(1000/ 500) × 0.46 = 0.92 M