choose the correct statement among the following.

Answers
we have to check the options :
solution : [FeCl₄]¯ => weak field ligands
Every weak field ligands with 3d series Central Metal Atom (Sc to Cu) is tetrahedral geometry.
so, [FeCl₄]¯ has tetrahedral geometry, option (A) is correct choice.
[Co(en)(HN3)2Cl2]⁺ has three geometrical isomers so option (2) is incorrect..
as [FeCl4]¯ has tetrahedral geometrical shape so it is sp³ hybridised and it has 5 unpaired electrons. while [Co(en)(HN3)2Cl2]⁺ is d²sp³ hybridised with zero unpaired electrons [ because configuration of Co³⁺ = [At]3d⁶ ].
hence it is clear that [FeCl4]¯ had higher sin only magnetic moment than [Co(en)(HN3)2Cl2]⁺, option (C) is correct choice.
[Co(en)(HN3)2Cl2]⁺ is d²sp³ hybridised and has octahedral geometry with zero unpaired electrons. so option (D) is incorrect
Therefore options (A) and (C) are correct choices.