Question

chord AB and CD of a circle with center O and radius 10 intersect each other in P at a right angle AB=18 and CD=16 find OP​

Answer 1

Answer:

Step-by-step explanation:

OP = PQ =radius=13 cm.

OQ = diameter=13*2= 26 cm

AB=CD=chords

M=the point at which the chords intersect.

PM= 5 cm

0M = OP - PM= 13-5= 8 cm

QM=PM + PQ = 13+5=18 cm

Hope it will help you with

Answer 2

Hey dear ‼️

plzz refer to the attached file..

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