Chord AB is at distance of 4 cm from the centre O of the circle . If the radius of the circle is 5 cm . Find the length of chord AB
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Answer:
Hey mate here is your answer
Step-by-step explanation:
By Pythagoras theorem
Obsquare = BM square + OM square
5 square = BM square +4 square
25 = BM square + 16
BM square = 25-16
= 9
BM = 3cm
AB = 2* BM
AB = 2*3
AB =6 cm
Answered by
3
by Pythagoras theorem :
OB²= BM² + OM²
5²=BM² + 4²
BM²= 5²- 4²
BM²= 25-16
BM²= 9
BM= 3
AB=2×BM
AB= 2×3
AB=6 cm.
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