Question

Each rectangular tile is 40 cm long and 30 cm wide. How many tiles will be required to
cover the floor of a room with length = 4.8 m and breadth = 24 m.​

Answer 1

Answer:

960

Step-by-step explanation:

area covered by 1 tile = 0.40 × 0.30 m2.

area of room to be covered=4.8×24 m2.

the number of tiles =area of room /area of 1 tile.

=4.8×24/0.40×0.30

=960

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Answer 2

${\tt{Length \: of \: tile = 40cm}}$

${\tt{Breadth \: of \: tile = 30cm}}$

$\red{\tt{Area \: of\:tile \: = l \times b}}$

$\pink{\tt{Area \: of \:tile}}$$\pink{\tt{ = 40 \times 30 = 1200 sqcm.}}$

${\tt{Length \: of \: floor =4.8m = 480cm}}$

${\tt{Breadth \: of \: floor = 24m = 2400cm}}$

$\pink{\tt{Area \: of\: floor }}$

$\pink{\tt{=2400 \times 480 = 1152000sqcm}}$

$\pink{\tt{The \: no. \: of \: tiles }}$

$\pink{\tt{needed = \frac{1152000}{1200} = 9600sqcm.}}$

$\huge{\boxed{\orange{9600sqcm.}}}$

$\huge{\bold{\underline{\underline{\purple{Follow\:me}}}}}$

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