Question

chord ab is at distance of 8cm less than e radius from the centre. radius of circle is less than chord by 11cm. Find the distance of the chord from the centre and the length of the chord​

Answer 1

Answer:

I think 2 ans

Step-by-step explanation:

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Answer 2

Answer:

• Given=chord ab=8cm
• and radius cb=11cm
• Let e the point on which the perpendicular lie
• A line drawn from the center of the circle to the chor it bisect the chord
• Eb = length of Ab÷2
• =8÷2=4cm
• by pythagoras theorem
• (Cb)2 = ( eb)2 + (ce)2
• (11)2 = ( 4)2 + (ce)2
• 121=16+(ce)2
• 121-16=(ce)2
• 105=(ce)2
• (Ce)=105
• =11cm