Chord ab is extended to meet tangent de at
d. If ab=5 and de=6 then find bd
debtwenty12pe7hvl:
is chord AB the diameter ?if it is then the problem can be solved else some information is missing
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Answer:
bd = 4 units
Step-by-step explanation:
For better understanding of the solution see the attached figure :
Let bd = x units ,
de = 6 units , ab = 5 units
⇒ ad = (x + 5) units
By using Secant Tangent theorem which states that : Product of the outside segment and whole secant equals the square of the tangent to the same point.
We get the following relation : de² = bd · ad
⇒ 6² = x · (x + 5)
⇒ 36 = x² + 5·x
⇒ x² + 5·x - 36 = 0
⇒ x² + 9·x - 4·x - 36 = 0
⇒ x·(x + 9) - 4·(x + 9) = 0
⇒ (x + 9)·(x -4) = 0
⇒ x = 4 or x = -9
But distance cannot be negative so x = -9 is discarded.
So, x = 4
Hence, the length of bd is 4 units.
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